4x^2=1286408

Solution for 4x^2=1286408 equation:

4x^2=1286408

We move all terms to the left:

4x^2-(1286408)=0

a = 4; b = 0; c = -1286408;
Δ = b2-4ac
Δ = 02-4·4·(-1286408)
Δ = 20582528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20582528}=\sqrt{10291264*2}=\sqrt{10291264}*\sqrt{2}=3208\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3208\sqrt{2}}{2*4}=\frac{0-3208\sqrt{2}}{8}
=-\frac{3208\sqrt{2}}{8}
=-401\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3208\sqrt{2}}{2*4}=\frac{0+3208\sqrt{2}}{8}
=\frac{3208\sqrt{2}}{8}
=401\sqrt{2}
$